3d^2+24d+45=0

解

3 d^{2} + 24 d + 45 = 0

d = - 3, d = - 5

解答ステップ

3 d^{2} + 24 d + 45 = 0

解くとthe二次式

d_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 45}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 45 = 6

d_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 3}

解を分離する

d_{1} = \frac{- 24 + 6}{2 \cdot 3}, d_{2} = \frac{- 24 - 6}{2 \cdot 3}

d = \frac{- 24 + 6}{2 \cdot 3} : - 3

d = \frac{- 24 - 6}{2 \cdot 3} : - 5

二次equationの解:

d = - 3, d = - 5