p^2-20p+100=0

解答

p^{2} - 20 p + 100 = 0

p = 10

求解步骤

p^{2} - 20 p + 100 = 0

使用求根公式求解

p_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 100 = 0

p_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 1}

p = \frac{- ( - 20 )}{2 \cdot 1}

\frac{- ( - 20 )}{2 \cdot 1} = 10

p = 10

二次方程组的解是:

p = 10

4 r^{2} + 8 r + 4 = 0

(6 X - 4) (3 X + 5) = (4 X - 9) (3 X + 5)

co m pl e t es q u a re m^{2} - 6 m + 8 = 0

4 x (x + 4) = 5 (x - 9)

9 x^{2} - 5 x - 2 = - 1 - x