What are the solutions to the equation 0=40x+75-3x^2 ?

The solutions to the equation 0=40x+75-3x^2 are x=-5/3 ,x=15

Find the zeros of 0=40x+75-3x^2

The zeros of 0=40x+75-3x^2 are x=-5/3 ,x=15

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0 = 40 x + 75 - 3 x^{2}

x = - \frac{5}{3}, x = 15

Decimal Notation

x = - 1.66666 \dots, x = 15

Solution steps

0 = 40 x + 75 - 3 x^{2}

Switch sides

40 x + 75 - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 40 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 3 ) \cdot 75}{2 ( - 3 )}

4 0^{2} - 4 (- 3) \cdot 75 = 50

x_{1, 2} = \frac{- 40 \pm 50}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 40 + 50}{2 ( - 3 )}, x_{2} = \frac{- 40 - 50}{2 ( - 3 )}

x = \frac{- 40 + 50}{2 ( - 3 )} : - \frac{5}{3}

x = \frac{- 40 - 50}{2 ( - 3 )} : 15

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = 15

\frac{4}{3} x + 8 \geq 3 (1 - \frac{1}{3 x})

g^{\frac{4}{7}} \cdot g^{\frac{3}{7}}

\frac{5}{6} x - 2 = \frac{7}{8}

2 x^{2} - 11 x - 2 = 0

2 k^{2} + 22 k = 74

What are the solutions to the equation 0=40x+75-3x^2 ?
The solutions to the equation 0=40x+75-3x^2 are x=-5/3 ,x=15
Find the zeros of 0=40x+75-3x^2
The zeros of 0=40x+75-3x^2 are x=-5/3 ,x=15