solvefor x,kx^2+8x+2k=0

解

x, k x^{2} + 8 x + 2 k = 0

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0

解答ステップ

k x^{2} + 8 x + 2 k = 0

解くとthe二次式

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 k \cdot 2 k}{2 k}

簡素化

8^{2} - 4 k \cdot 2 k : 64 - 8 k^{2}

x_{1, 2} = \frac{- 8 \pm 64 - 8 k ^{2}}{2 k}; k \neq = 0

解を分離する

x_{1} = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x_{2} = \frac{- 8 - 64 - 8 k ^{2}}{2 k}

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}; k \neq = 0

x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0

二次equationの解:

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0