y=log_{10}(1)

Lösung

y = lo g_{10} (1)

y = 0

Schritte zur Lösung

y = lo g_{10} (1)

Wende die log Regel an:

lo g_{a} (1) = 0

y = 0

- 4 (2 m - 7) = 3 (52 - 4 m)

- 2 (3 - d) = 4

\frac{x + 3}{7} + \frac{x - 1}{14} = \frac{x + 1}{2}

- \frac{4}{3} t + \frac{1}{2} = \frac{3}{2} - 2 t + \frac{5}{3} t

5 m + 10 p = 20 n