solvefor g,2log_{10}(x)=log_{2}(+log_{10}(3x-4))

Lösung

löse nach

g, 2 lo g_{10} (x) = lo g_{2} (+ lo g_{10} (3 x - 4))

Wahr f \overset{u}{¨} r alle g; 2 lo g_{10} (x) = lo g_{2} (lo g_{10} (3 x - 4))

Schritte zur Lösung

2 lo g_{10} (x) = lo g_{2} (lo g_{10} (3 x - 4))

Beide Seiten sind gleich

Wahr f \overset{u}{¨} r alle g; 2 lo g_{10} (x) = lo g_{2} (lo g_{10} (3 x - 4))

\frac{x - 4}{3} + 5 = 0

f = - 2 (0) + 1

0 = 4

1 = x

3 m + 8 \frac{1}{4} = 9