What are the solutions to the equation 34=100t-16t^2 ?

The solutions to the equation 34=100t-16t^2 are t=(25-sqrt(489))/8 ,t=(25+sqrt(489))/8

Find the zeros of 34=100t-16t^2

The zeros of 34=100t-16t^2 are t=(25-sqrt(489))/8 ,t=(25+sqrt(489))/8

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34 = 100 t - 16 t^{2}

t = \frac{25 - 489}{8}, t = \frac{25 + 489}{8}

Decimal Notation

t = 0.36083 \dots, t = 5.88916 \dots

Solution steps

34 = 100 t - 16 t^{2}

Switch sides

100 t - 16 t^{2} = 34

Move

34

to the left side

100 t - 16 t^{2} - 34 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 100 t - 34 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 16 ) ( - 34 )}{2 ( - 16 )}

10 0^{2} - 4 (- 16) (- 34) = 4489

t_{1, 2} = \frac{- 100 \pm 4 489}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 100 + 4 489}{2 ( - 16 )}, t_{2} = \frac{- 100 - 4 489}{2 ( - 16 )}

t = \frac{- 100 + 4 489}{2 ( - 16 )} : \frac{25 - 489}{8}

t = \frac{- 100 - 4 489}{2 ( - 16 )} : \frac{25 + 489}{8}

The solutions to the quadratic equation are:

t = \frac{25 - 489}{8}, t = \frac{25 + 489}{8}

- 4 i y - 5 + 2 i

4 k - 6 = - 2 k - 16 - 2

10 b - 4 b^{3}

\frac{m ^{3} n ^{2}}{m n ^{3}}

x^{2} - 5 x + 12 = 0

What are the solutions to the equation 34=100t-16t^2 ?
The solutions to the equation 34=100t-16t^2 are t=(25-sqrt(489))/8 ,t=(25+sqrt(489))/8
Find the zeros of 34=100t-16t^2
The zeros of 34=100t-16t^2 are t=(25-sqrt(489))/8 ,t=(25+sqrt(489))/8