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Frequently Asked Questions (FAQ)
What are the solutions to the equation 0=7x+4.9x^2-8 ?
- The solutions to the equation 0=7x+4.9x^2-8 are x=(-5+sqrt(105))/7 ,x=-(5+sqrt(105))/7
Find the zeros of 0=7x+4.9x^2-8
- The zeros of 0=7x+4.9x^2-8 are x=(-5+sqrt(105))/7 ,x=-(5+sqrt(105))/7