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受欢迎的代数 >

15=a_{0}(s+3)+a_{1}s

解答

15 = a_{0} (s + 3) + a_{1} s

解答

s = \frac{15 - 3 a _{0}}{a _{0} + a _{1}}; a_{0} \neq = - a_{1}

求解步骤

15 = a_{0} (s + 3) + a_{1} s

交换两边

a_{0} (s + 3) + a_{1} s = 15

乘开

a_{0} (s + 3) : a_{0} s + 3 a_{0}

a_{0} s + 3 a_{0} + a_{1} s = 15

将

3 a_{0}

到右边

a_{0} s + a_{1} s = 15 - 3 a_{0}

分解

a_{0} s + a_{1} s : s (a_{0} + a_{1})

s (a_{0} + a_{1}) = 15 - 3 a_{0}

两边除以

a_{0} + a_{1}; a_{0} \neq = - a_{1}

s = \frac{15 - 3 a _{0}}{a _{0} + a _{1}}; a_{0} \neq = - a_{1}

作图

流行的例子

7 x = 3 x + 20

(2x-1)/5-x/6 =(8-3x)/(10)

\frac{2 x - 1}{5} - \frac{x}{6} = \frac{8 - 3 x}{10}

\frac{x}{5} - \frac{2}{3} + x = 0

solvefor y,8+3y=1+9x

so l v e f or y, 8 + 3 y = 1 + 9 x

\frac{x}{4} + \frac{x}{3} = x - 100