解
簡約 20ei30100e−i45
解
cos2(30)+sin2(30)5cos(30)cos(45)−5sin(30)sin(45)+icos2(30)+sin2(30)−5cos(30)sin(45)−5cos(45)sin(30)
解答ステップ
20ei30100e−i45
100e−i45=100(cos(45)−isin(45))
=20e30i100(−isin(45)+cos(45))
20ei30=20(cos(30)+isin(30))
=20(cos(30)+isin(30))100(−isin(45)+cos(45))
数を割る:20100=5=(cos(30)+isin(30))5(−isin(45)+cos(45))
複素数の算術規則を適用する: c+dia+bi=(c−di)(c+di)(c−di)(a+bi)=c2+d2(ac+bd)+(bc−ad)ia=5cos(45),b=−5sin(45),c=cos(30),d=sin(30)=cos2(30)+sin2(30)(5cos(45)cos(30)+(−5sin(45))sin(30))+(−5sin(45)cos(30)−5cos(45)sin(30))i
改良=cos2(30)+sin2(30)(5cos(45)cos(30)−5sin(45)sin(30))+(−5sin(45)cos(30)−5cos(45)sin(30))i
簡素化 cos2(30)+sin2(30)(5cos(45)cos(30)−5sin(45)sin(30))+(−5sin(45)cos(30)−5cos(45)sin(30))i:cos2(30)+sin2(30)5cos(45)cos(30)−5sin(45)sin(30)+i(−5sin(45)cos(30)−5cos(45)sin(30))
=cos2(30)+sin2(30)5cos(45)cos(30)−5sin(45)sin(30)+i(−5sin(45)cos(30)−5cos(45)sin(30))
標準的な複素数形式で cos2(30)+sin2(30)5cos(45)cos(30)−5sin(45)sin(30)+i(−5sin(45)cos(30)−5cos(45)sin(30)) を書き換える:cos2(30)+sin2(30)5cos(45)cos(30)−5sin(45)sin(30)+cos2(30)+sin2(30)−5sin(45)cos(30)−5cos(45)sin(30)i
=cos2(30)+sin2(30)5cos(45)cos(30)−5sin(45)sin(30)+cos2(30)+sin2(30)−5sin(45)cos(30)−5cos(45)sin(30)i