展开 2(pi-θ)

解答

展开

2 (π - θ)

2 π - 2 θ

求解步骤

2 (π - θ)

使用分配律:

a (b - c) = ab - a c

a = 2, b = π, c = θ

= 2 π - 2 θ

e x p an d \frac{s ^{2} - s + 1}{( s + 1 ) ^{2}}

e x p an d - \frac{( 6 x ^{2} + 11 x + 7 )}{( x ^{2} + 5 ) ( x + 3 )}

e x p an d (3 - x - 1) (6 - x + 2)

e x p an d \frac{3 x}{( x - 1 ) ( x - 4 ) ^{2}}

e x p an d - ((- 1, 0, 2) + 3 (3, - 1, - 2))