erweitern (7(3-3z)^2)/2

Lösung

erweitern

\frac{7 ( 3 - 3 z ) ^{2}}{2}

\frac{63 z ^{2}}{2} - 63 z + \frac{63}{2}

Schritte zur Lösung

\frac{7 ( 3 - 3 z ) ^{2}}{2}

(3 - 3 z)^{2} = 9 - 18 z + 9 z^{2}

= \frac{7 ( 9 z ^{2} - 18 z + 9 )}{2}

Multipliziere aus

7 (9 - 18 z + 9 z^{2}) : 63 - 126 z + 63 z^{2}

= \frac{63 - 126 z + 63 z ^{2}}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{63 - 126 z + 63 z ^{2}}{2} = \frac{63}{2} - \frac{126 z}{2} + \frac{63 z ^{2}}{2}

= \frac{63}{2} - \frac{126 z}{2} + \frac{63 z ^{2}}{2}

Teile die Zahlen:

\frac{126}{2} = 63

= \frac{63}{2} - 63 z + \frac{63 z ^{2}}{2}

Rewrite in standard form

= \frac{63 z ^{2}}{2} - 63 z + \frac{63}{2}

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