展开 d(id=id-i*b)

解答

展开

d (i \cdot d = i \cdot d - i \cdot b)

i d^{2} = i d - i d^{2} = i d b

求解步骤

d (i d = i d - ib)

= d (ii = dd - ib)

乘开

d (i d = i d - ib) : i d^{2} = i (d - d b)

i d^{2} = i (d - d b)

乘开

i d^{2} = i (d - d b) : i d^{2} = i d - i d^{2} = i d b

i d^{2} = i d - i d^{2} = i d b

e x p an d \frac{2 x}{( 2 x + 1 ) ^{4}}

e x p an d - \frac{5}{4} \cdot \frac{x - 5}{2 x}

\frac{d}{d t} ((x) (a (t - sin (t))))

e x p an d C (1, - 1) F (1, 2) A (1, 4)

e x p an d a (13 + (- 13) = 0)