|4x+3|=(x-1)(x+1)+1

解

∣ 4 x + 3 ∣ = (x - 1) (x + 1) + 1

x = - 3 or x = - 1 or x = 2 - 7 or x = 2 + 7

十進法表記

x = - 3, x = - 1, x = - 0.64575 \dots, x = 4.64575 \dots

解答ステップ

∣ 4 x + 3 ∣ = (x - 1) (x + 1) + 1

正と負の区間を求める

x < - \frac{3}{4}, x \geq - \frac{3}{4}

各区間の不等式を解く

(x = - 3 or x = - 1) or (x = 2 - 7 or x = 2 + 7)

x = - 3 or x = - 1 or x = 2 - 7 or x = 2 + 7