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受欢迎的代数 >

1.1t^2-1.2t+0.3=0

解答

1.1 t^{2} - 1.2 t + 0.3 = 0

解答

t = \frac{6 + 3}{11}, t = \frac{6 - 3}{11}

+1

十进制

t = 0.70291 \dots, t = 0.38799 \dots

求解步骤

1.1 t^{2} - 1.2 t + 0.3 = 0

在两边乘以

10

11 t^{2} - 12 t + 3 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 11 \cdot 3}{2 \cdot 11}

(- 12)^{2} - 4 \cdot 11 \cdot 3 = 23

t_{1, 2} = \frac{- ( - 12 ) \pm 2 3}{2 \cdot 11}

将解分隔开

t_{1} = \frac{- ( - 12 ) + 2 3}{2 \cdot 11}, t_{2} = \frac{- ( - 12 ) - 2 3}{2 \cdot 11}

t = \frac{- ( - 12 ) + 2 3}{2 \cdot 11} : \frac{6 + 3}{11}

t = \frac{- ( - 12 ) - 2 3}{2 \cdot 11} : \frac{6 - 3}{11}

二次方程组的解是:

t = \frac{6 + 3}{11}, t = \frac{6 - 3}{11}

作图

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111 x^{2} - 468 x + 456 = 0

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