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受欢迎的代数 >

n^1+n^2=4,0=24

解答

n^{1} + n^{2} = 4, 0 = 24

解答

n = \frac{- 1 + 17}{2}, n = \frac{- 1 - 17}{2}

+1

十进制

n = 1.56155 \dots, n = - 2.56155 \dots

求解步骤

n^{1} + n^{2} = 4

整理后得

n + n^{2} = 4

将

4

para o lado esquerdo

n + n^{2} - 4 = 0

改写成标准形式

a x^{2} + b x + c = 0

n^{2} + n - 4 = 0

使用求根公式求解

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 4) = 17

n_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

将解分隔开

n_{1} = \frac{- 1 + 17}{2 \cdot 1}, n_{2} = \frac{- 1 - 17}{2 \cdot 1}

n = \frac{- 1 + 17}{2 \cdot 1} : \frac{- 1 + 17}{2}

n = \frac{- 1 - 17}{2 \cdot 1} : \frac{- 1 - 17}{2}

二次方程组的解是:

n = \frac{- 1 + 17}{2}, n = \frac{- 1 - 17}{2}

作图

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