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受欢迎的代数 >

j(x)=x^2+2x+1

解答

j (x) = x^{2} + 2 x + 1

解答

x = \frac{- 2 + j + j ^{2} - 4 j}{2}, x = \frac{- 2 + j - j ^{2} - 4 j}{2}

求解步骤

j (x) = x^{2} + 2 x + 1

整理后得

j x = x^{2} + 2 x + 1

交换两边

x^{2} + 2 x + 1 = j x

将

j x

para o lado esquerdo

x^{2} + 2 x + 1 - j x = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (2 - j) x + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 2 - j ) \pm ( 2 - j ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

化简

(2 - j)^{2} - 4 \cdot 1 \cdot 1 : j^{2} - 4 j

x_{1, 2} = \frac{- ( 2 - j ) \pm j ^{2} - 4 j}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 2 - j ) + j ^{2} - 4 j}{2 \cdot 1}, x_{2} = \frac{- ( 2 - j ) - j ^{2} - 4 j}{2 \cdot 1}

x = \frac{- ( 2 - j ) + j ^{2} - 4 j}{2 \cdot 1} : \frac{- 2 + j + j ^{2} - 4 j}{2}

x = \frac{- ( 2 - j ) - j ^{2} - 4 j}{2 \cdot 1} : \frac{- 2 + j - j ^{2} - 4 j}{2}

二次方程组的解是:

x = \frac{- 2 + j + j ^{2} - 4 j}{2}, x = \frac{- 2 + j - j ^{2} - 4 j}{2}

作图

流行的例子

4 x^{2} - 30 x + 50 = 0

solvefor y,x=5(y+7)(y-8)

so l v e f or y, x = 5 (y + 7) (y - 8)

(4x-2)/5 =x^2-2/3

\frac{4 x - 2}{5} = x^{2} - \frac{2}{3}

1 3^{2} = 5^{2} + b^{2}

solvefor x,36x^2+25y^2+z^2=1

so l v e f or x, 36 x^{2} + 25 y^{2} + z^{2} = 1