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受欢迎的代数 >

6t^2+6t+14=sqrt(2)

解答

6 t^{2} + 6 t + 14 = 2

解答

t = - \frac{1}{2} + i \frac{300 - 24 2}{12}, t = - \frac{1}{2} - i \frac{300 - 24 2}{12}

求解步骤

6 t^{2} + 6 t + 14 = 2

将

2

para o lado esquerdo

6 t^{2} + 6 t + 14 - 2 = 0

使用求根公式求解

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( 14 - 2 )}{2 \cdot 6}

化简

6^{2} - 4 \cdot 6 (14 - 2) : i 300 - 242

t_{1, 2} = \frac{- 6 \pm i 300 - 24 2}{2 \cdot 6}

将解分隔开

t_{1} = \frac{- 6 + i 300 - 24 2}{2 \cdot 6}, t_{2} = \frac{- 6 - i 300 - 24 2}{2 \cdot 6}

t = \frac{- 6 + i 300 - 24 2}{2 \cdot 6} : - \frac{1}{2} + i \frac{300 - 24 2}{12}

t = \frac{- 6 - i 300 - 24 2}{2 \cdot 6} : - \frac{1}{2} - i \frac{300 - 24 2}{12}

二次方程组的解是:

t = - \frac{1}{2} + i \frac{300 - 24 2}{12}, t = - \frac{1}{2} - i \frac{300 - 24 2}{12}

作图

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