化简 (1/((4ab^2c)))^2+(3/((2a^2bc^2)))^4

解答

化简

(\frac{1}{( 4 a \cdot b ^{2} \cdot c )})^{2} + (\frac{3}{( 2 a ^{2} \cdot b \cdot c ^{2} )})^{4}

\frac{1}{16 a ^{2} b ^{4} c ^{2}} + \frac{81}{16 a ^{8} b ^{4} c ^{8}}

求解步骤

(\frac{1}{4 a b ^{2} c})^{2} + (\frac{3}{2 a ^{2} b c ^{2}})^{4}

(\frac{1}{4 a b ^{2} c})^{2} = \frac{1}{16 a ^{2} b ^{4} c ^{2}}

(\frac{3}{2 a ^{2} b c ^{2}})^{4} = \frac{81}{16 a ^{8} b ^{4} c ^{8}}

= \frac{1}{16 a ^{2} b ^{4} c ^{2}} + \frac{81}{16 a ^{8} b ^{4} c ^{8}}

e x p an d (2 x^{2} + y) (2 x + y)

e x p an d (3 + 2 b)^{8}

s im pl i f y (\frac{1}{3} \cdot a^{2} - \frac{3}{2} \cdot b^{2})^{2}

s im pl i f y \frac{( 9 x 1 0 ^{9} \cdot 2 x 1 0 ^{- 5} )}{0. 4 ^{2}}

s im pl i f y (x^{6})^{3} (x^{2})