簡約 8x+[9x{6x(5x-4x)}]+14x-{11x[7x(3x-2x)]}

解

簡約

8 x + [9 x {6 x (5 x - 4 x)}] + 14 x - {11 x [7 x (3 x - 2 x)]}

22 x - 23 x^{3}

解答ステップ

8 x + (9 x (6 x (5 x - 4 x))) + 14 x - (11 x (7 x (3 x - 2 x)))

簡素化

8 x + (9 x (6 x (5 x - 4 x))) + 14 x - (11 x (7 x (3 x - 2 x))) : 8 x + 9 x (6 x (5 x - 4 x)) + 14 x - 11 x (7 x (3 x - 2 x))

= 8 x + 9 x \cdot 6 x (5 x - 4 x) + 14 x - 11 x \cdot 7 x (3 x - 2 x)

条件のようなグループ

= 8 x + 14 x + 9 x \cdot 6 x (5 x - 4 x) - 11 x \cdot 7 x (3 x - 2 x)

類似した元を足す:

8 x + 14 x = 22 x

= 22 x + 9 x \cdot 6 x (5 x - 4 x) - 11 x \cdot 7 x (3 x - 2 x)

9 x \cdot 6 x (5 x - 4 x) = 54 x^{3}

11 x \cdot 7 x (3 x - 2 x) = 77 x^{3}

= 22 x + 54 x^{3} - 77 x^{3}

類似した元を足す:

54 x^{3} - 77 x^{3} = - 23 x^{3}

= 22 x - 23 x^{3}