faktorisieren x^{15}+x^9+x^6+1

Lösung

faktorisieren

x^{15} + x^{9} + x^{6} + 1

(x^{2} + 1) (x^{4} - x^{2} + 1) (x + 1) (x^{2} - x + 1) (x^{6} - x^{3} + 1)

Schritte zur Lösung

x^{15} + x^{9} + x^{6} + 1

= (x^{15} + x^{9}) + (x^{6} + 1)

Klammere

x^{9}

aus

x^{15} + x^{9}

aus

: x^{9} (x^{6} + 1)

= x^{9} (x^{6} + 1) + (x^{6} + 1)

Klammere gleiche Terme aus

(x^{6} + 1) : (x^{6} + 1) (x^{9} + 1)

= (x^{6} + 1) (x^{9} + 1)

Faktorisiere

x^{6} + 1 : (x^{2} + 1) (x^{4} - x^{2} + 1)

= (x^{2} + 1) (x^{4} - x^{2} + 1) (x^{9} + 1)

Faktorisiere

x^{9} + 1 : (x + 1) (x^{2} - x + 1) (x^{6} - x^{3} + 1)

= (x^{2} + 1) (x^{4} - x^{2} + 1) (x + 1) (x^{2} - x + 1) (x^{6} - x^{3} + 1)

s im pl i f y lo g_{10} (a + b) (a^{2})

s im pl i f y b - 3 - 1415.5

s im pl i f y 5 ∣ x - 2 ∣^{2}

s im pl i f y \frac{( ( a - b ) ^{3} + ( b - c ) ^{3} + ( c - a ) ^{3} )}{( 9 ( a - b ) ( b - c ) ( c - a ) )}

s im pl i f y 2 (cos (o) + i \cdot sin (0))