化简 z^2+2iz+(2-4i)

解答

化简

z^{2} + 2 i z + (2 - 4 i)

(z^{2} + 2) + (2 z - 4) i

求解步骤

z^{2} + 2 i z + (2 - 4 i)

Rewrite in standard complex form:

z^{2} + 2 z i + (2 - 4 i)

= z^{2} + 2 z i + 2 - 4 i

将复数的实部和虚部分组

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (z^{2} + 2) + (2 z - 4) i

e x p an d (2 x + 11)^{3}

e x p an d (0.2 m - 3 n) \cdot x^{0.7} m

e x p an d (4 a^{4} - 2 b^{3})^{3}

s im pl i f y \frac{[ ( 2 x - 4 ) 3 ]}{2}

e x p an d (3 a + 5 b)^{2} - 4 c^{2}