a(n+2)-5a(n+1)+6a(n)=2

解

a (n + 2) - 5 a (n + 1) + 6 a (n) = 2

a = \frac{2}{2 n - 3}; n \neq = \frac{3}{2}

解答ステップ

a (n + 2) - 5 a (n + 1) + 6 a (n) = 2

a (n + 2) - 5 a (n + 1) + 6 na = 2

拡張

a (n + 2) - 5 a (n + 1) + 6 na : 2 na - 3 a

2 na - 3 a = 2

因数

2 na - 3 a : a (2 n - 3)

a (2 n - 3) = 2

以下で両辺を割る

2 n - 3; n \neq = \frac{3}{2}

a = \frac{2}{2 n - 3}; n \neq = \frac{3}{2}