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Beliebt Algebra >

(2x+3)(x-4)=(x+2)(4x^2-9)

Lösung

(2 x + 3) \cdot (x - 4) = (x + 2) \cdot (4 x^{2} - 9)

Lösung

x = - 1, x = 1, x = - \frac{3}{2}

+1

Dezimale

x = - 1, x = 1, x = - 1.5

Schritte zur Lösung

(2 x + 3) (x - 4) = (x + 2) (4 x^{2} - 9)

Verschiebe

(x + 2) \cdot (4 x^{2} - 9)

auf die linke Seite

(2 x + 3) (x - 4) - (x + 2) (4 x^{2} - 9) = 0

Faktorisiere

(2 x + 3) (x - 4) - (x + 2) (4 x^{2} - 9) : - 2 (x + 1) (x - 1) (2 x + 3)

- 2 (x + 1) (x - 1) (2 x + 3) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x + 1 = 0 or x - 1 = 0 or 2 x + 3 = 0

Löse

x + 1 = 0 : x = - 1

Löse

x - 1 = 0 : x = 1

Löse

2 x + 3 = 0 : x = - \frac{3}{2}

Die Lösungen sind

x = - 1, x = 1, x = - \frac{3}{2}

Graph

Beliebte Beispiele

solvefor c,x^3+3x^2*y+y^3=c^3

so l v e f or c, x^{3} + 3 x^{2} \cdot y + y^{3} = c^{3}

x^{4} - 15 x^{2} - 16 = 0

solvefor x,x^3-19=y^3

so l v e f or x, x^{3} - 19 = y^{3}

x^{3} (x - 2) = 0

125x^3+150x^2+60x=0

125 x^{3} + 150 x^{2} + 60 x = 0