x^2+4x-b*x^2+8-a=0

Lösung

x^{2} + 4 x - b \cdot x^{2} + 8 - a = 0

x = \frac{- 2 + 8 b - ba + a - 4}{1 - b}, x = - \frac{8 b - ba + a - 4 + 2}{- b + 1}; b \neq = 1

Schritte zur Lösung

x^{2} + 4 x - b x^{2} + 8 - a = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

(1 - b) x^{2} + 4 x + 8 - a = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( 1 - b ) ( 8 - a )}{2 ( 1 - b )}

Vereinfache

4^{2} - 4 (1 - b) (8 - a) : 2 8 b - ba + a - 4

x_{1, 2} = \frac{- 4 \pm 2 8 b - ba + a - 4}{2 ( 1 - b )}; b \neq = 1

Trenne die Lösungen

x_{1} = \frac{- 4 + 2 8 b - ba + a - 4}{2 ( 1 - b )}, x_{2} = \frac{- 4 - 2 8 b - ba + a - 4}{2 ( 1 - b )}

x = \frac{- 4 + 2 8 b - ba + a - 4}{2 ( 1 - b )} : \frac{- 2 + 8 b - ba + a - 4}{1 - b}

x = \frac{- 4 - 2 8 b - ba + a - 4}{2 ( 1 - b )} : - \frac{8 b - ba + a - 4 + 2}{- b + 1}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- 2 + 8 b - ba + a - 4}{1 - b}, x = - \frac{8 b - ba + a - 4 + 2}{- b + 1}; b \neq = 1

x^{2} - 25 = a^{2} - b^{2}

(m - 2) \cdot x^{2} - (3 m - 8) x + m - 9 = 0

2 - x^{2} = 2

x^{2} + a = 25

so l v e f or x, x^{2} + y^{2} - 4 x - 6 y + 19 = 0