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受欢迎的代数 >

solvefor x,f=m(x+1)^2+n

解答

求解

x, f = m (x + 1)^{2} + n

解答

x = \frac{f - n}{m} - 1, x = - \frac{f - n}{m} - 1; m \neq = 0

求解步骤

f = m (x + 1)^{2} + n

交换两边

m (x + 1)^{2} + n = f

将

n

到右边

m (x + 1)^{2} = f - n

两边除以

m; m \neq = 0

(x + 1)^{2} = \frac{f - n}{m}; m \neq = 0

对于

(g (x))^{2} = f (a)

解为

g (x) = f (a), - f (a)

解

x + 1 = \frac{f - n}{m} : x = \frac{f - n}{m} - 1

解

x + 1 = - \frac{f - n}{m} : x = - \frac{f - n}{m} - 1

二次方程组的解是:

x = \frac{f - n}{m} - 1, x = - \frac{f - n}{m} - 1; m \neq = 0

作图

流行的例子

9 = 3 m^{2} + 2 (m - 13)

v^2-9.8^2=2*9.8*19.6

v^{2} - 9. 8^{2} = 2 \cdot 9.8 \cdot 19.6

(4x-1)^2+(-2)^3=2020

(4 x - 1)^{2} + (- 2)^{3} = 2020

(k+2)*x^2-13x+4k-10=0

(k + 2) \cdot x^{2} - 13 x + 4 k - 10 = 0

(7 - 2 f)^{2} = 9