2a^2-8a+800=0

解答

2 a^{2} - 8 a + 800 = 0

a = 2 + 611 i, a = 2 - 611 i

求解步骤

2 a^{2} - 8 a + 800 = 0

使用求根公式求解

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 800}{2 \cdot 2}

化简

(- 8)^{2} - 4 \cdot 2 \cdot 800 : 2411 i

a_{1, 2} = \frac{- ( - 8 ) \pm 24 11 i}{2 \cdot 2}

将解分隔开

a_{1} = \frac{- ( - 8 ) + 24 11 i}{2 \cdot 2}, a_{2} = \frac{- ( - 8 ) - 24 11 i}{2 \cdot 2}

a = \frac{- ( - 8 ) + 24 11 i}{2 \cdot 2} : 2 + 611 i

a = \frac{- ( - 8 ) - 24 11 i}{2 \cdot 2} : 2 - 611 i

二次方程组的解是:

a = 2 + 611 i, a = 2 - 611 i

3 x^{2} - 43 x - 6 = 0

2 x^{2} - 16 x = 12 x + 48

(\frac{5 x - 1}{3})^{2} = \frac{4}{9}

x^{2} + 2 (m + 1) x - 3 m (m - 2) = 0

so l v e f or x, f = f (x^{2}) - 2 f (1)