zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

(q)=3q^2+5q+10

解答

(q) = 3 q^{2} + 5 q + 10

解答

q = - \frac{2}{3} + i \frac{26}{3}, q = - \frac{2}{3} - i \frac{26}{3}

求解步骤

(q) = 3 q^{2} + 5 q + 10

整理后得

q = 3 q^{2} + 5 q + 10

交换两边

3 q^{2} + 5 q + 10 = q

将

q

para o lado esquerdo

3 q^{2} + 4 q + 10 = 0

使用求根公式求解

q_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

化简

4^{2} - 4 \cdot 3 \cdot 10 : 226 i

q_{1, 2} = \frac{- 4 \pm 2 26 i}{2 \cdot 3}

将解分隔开

q_{1} = \frac{- 4 + 2 26 i}{2 \cdot 3}, q_{2} = \frac{- 4 - 2 26 i}{2 \cdot 3}

q = \frac{- 4 + 2 26 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{26}{3}

q = \frac{- 4 - 2 26 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{26}{3}

二次方程组的解是:

q = - \frac{2}{3} + i \frac{26}{3}, q = - \frac{2}{3} - i \frac{26}{3}

作图

流行的例子

4.9t^2+12t-171=0

4.9 t^{2} + 12 t - 171 = 0

16 x^{2} - 102 + 44 = 0

z^{2} - 2 z = - 5

x^{2} = 0.0081

solvefor x,3x7-4x^2y+xy^3=25

so l v e f or x, 3 x 7 - 4 x^{2} y + x y^{3} = 25