|1-z|=1,|z|=1

Lösung

∣ 1 - z ∣ = 1, ∣ z ∣ = 1

z = 0 or z = 2

Schritte zur Lösung

∣ 1 - z ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

1 - z = - 1 or 1 - z = 1

1 - z = - 1 or 1 - z = 1

z = 0 or z = 2

∣ - 5 (x - 3) ∣ = 30

∣ 7 x + 4 ∣ = x + 2

1 ∣ x + 2 ∣ = 2 (3 - x)

lo g_{2} (x - 6) = 6

ln (x) = - 1