What is 11>= 3x-7x+3-1 ?

The solution to 11>= 3x-7x+3-1 is x>=-9/4

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11>= 3x-7x+3-1

11 \geq 3 x - 7 x + 3 - 1

x \geq - \frac{9}{4}

Interval Notation

[- \frac{9}{4}, \infty)

Decimal Notation

x \geq - 2.25

Solution steps

11 \geq 3 x - 7 x + 3 - 1

Switch sides

3 x - 7 x + 3 - 1 \leq 11

Add similar elements:

3 x - 7 x = - 4 x

- 4 x + 3 - 1 \leq 11

Add/Subtract the numbers:

3 - 1 = 2

- 4 x + 2 \leq 11

Move

2

to the right side

- 4 x \leq 9

Multiply both sides by

- 1

4 x \geq - 9

Divide both sides by

4

x \geq - \frac{9}{4}

\frac{2 ^{3}}{2 ^{5}}

- 4 x^{2} > 16

x^{2} + 7 x + 22 = 0

10 - 4 x \leq 7

\frac{2 x ^{2} + 8 x - 3}{x ^{2} + 3 x + 2}