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Beliebt Algebra >

4/((x-1))>= 1/((2x-1))

Lösung

\frac{4}{( x - 1 )} \geq \frac{1}{( 2 x - 1 )}

Lösung

\frac{3}{7} \leq x < \frac{1}{2} or x > 1

+2

Intervall-Notation

[\frac{3}{7}, \frac{1}{2}) \cup (1, \infty)

Dezimale

0.42857 \dots \leq x < 0.5 or x > 1

Schritte zur Lösung

\frac{4}{x - 1} \geq \frac{1}{2 x - 1}

Rewrite in standard form

\frac{7 x - 3}{( x - 1 ) ( 2 x - 1 )} \geq 0

Identifiziere die Intervalle

\frac{3}{7} \leq x < \frac{1}{2} or x > 1

Graph

Beliebte Beispiele

((x-5))/((x^2+x+5)(x^2-4x-5))>0

\frac{( x - 5 )}{( x ^{2} + x + 5 ) ( x ^{2} - 4 x - 5 )} > 0

(((x-1)^2*(x+1)^3))/((x^4*(x-2)))<= 0

\frac{( ( x - 1 ) ^{2} \cdot ( x + 1 ) ^{3} )}{( x ^{4} \cdot ( x - 2 ) )} \leq 0

(x^{2} - 1) (x - 2) > 0

(x^2-x)^2+3(x^2-x)>0

(x^{2} - x)^{2} + 3 (x^{2} - x) > 0

3/((2x-1))>= 5/((x-1))

\frac{3}{( 2 x - 1 )} \geq \frac{5}{( x - 1 )}