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Beliebt Algebra >

(x+1)(x^2+x-1)<(x+1)

Lösung

(x + 1) (x^{2} + x - 1) < (x + 1)

Lösung

x < - 2 or - 1 < x < 1

+1

Intervall-Notation

(- \infty, - 2) \cup (- 1, 1)

Schritte zur Lösung

(x + 1) (x^{2} + x - 1) < x + 1

Rewrite in standard form

x^{3} + 2 x^{2} - 2 - x < 0

Faktorisiere

x^{3} + 2 x^{2} - 2 - x : (x + 2) (x + 1) (x - 1)

(x + 2) (x + 1) (x - 1) < 0

Identifiziere die Intervalle

x < - 2 or - 1 < x < 1

Graph

Beliebte Beispiele

(x-1)^2*(x+1)^3*(x-4)>= 0

(x - 1)^{2} \cdot (x + 1)^{3} \cdot (x - 4) \geq 0

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2x^2+2x+1<(15)/((x^2+x+1))

2 x^{2} + 2 x + 1 < \frac{15}{( x ^{2} + x + 1 )}