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Beliebt Algebra >

x^2(x+3)(x-5)^3*(x-7)^4>= 0

Lösung

x^{2} \cdot (x + 3) \cdot (x - 5)^{3} \cdot (x - 7)^{4} \geq 0

Lösung

x \leq - 3 or x = 0 or x \geq 5

+1

Intervall-Notation

(- \infty, - 3] \cup x = 0 \cup [5, \infty)

Schritte zur Lösung

x^{2} (x + 3) (x - 5)^{3} (x - 7)^{4} \geq 0

Identifiziere die Intervalle

x \leq - 3 or x = 0 or x \geq 5

Graph

Beliebte Beispiele

(2+3)/((x+1))>= 2/x

\frac{2 + 3}{( x + 1 )} \geq \frac{2}{x}

((x+3))/((5x))>0

\frac{( x + 3 )}{( 5 x )} > 0

3 x + \frac{8}{x} - 1 < - \frac{2}{1}

((-x+5))/((x-2))<0

\frac{( - x + 5 )}{( x - 2 )} < 0

\frac{3}{( x - 2 )} < 0