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Beliebt Algebra >

x(x+2)^2(x-1)^5(2x-3)(x-3)^4>= 0

Lösung

x \cdot (x + 2)^{2} \cdot (x - 1)^{5} \cdot (2 x - 3) \cdot (x - 3)^{4} \geq 0

Lösung

x = - 2 or 0 \leq x \leq 1 or x \geq \frac{3}{2}

+2

Intervall-Notation

x = - 2 \cup [0, 1] \cup [\frac{3}{2}, \infty)

Dezimale

x = - 2 or 0 \leq x \leq 1 or x \geq 1.5

Schritte zur Lösung

x (x + 2)^{2} (x - 1)^{5} (2 x - 3) (x - 3)^{4} \geq 0

Identifiziere die Intervalle

x = - 2 or 0 \leq x \leq 1 or x \geq \frac{3}{2}

Graph

Beliebte Beispiele

((x^2-2x)(2x-2)-9*(2x-2))/((x^2-2x))<= 0

\frac{( x ^{2} - 2 x ) ( 2 x - 2 ) - 9 \cdot ( 2 x - 2 )}{( x ^{2} - 2 x )} \leq 0

(((2x+1)(x+4)))/((x^2))>= 0

\frac{( ( 2 x + 1 ) ( x + 4 ) )}{( x ^{2} )} \geq 0

(x^2-16)*(x^2-4)<0

(x^{2} - 16) \cdot (x^{2} - 4) < 0

(x-2)(x-2)-15<x-2+x-2

(x - 2) (x - 2) - 15 < x - 2 + x - 2

3 x^{2} - 4 < 5