(-18m^2)^2-4(1+m^2)(81m^2-49)=0

Lösung

(- 18 m^{2})^{2} - 4 (1 + m^{2}) (81 m^{2} - 49) = 0

m = - \frac{7}{4 2}, m = \frac{7}{4 2}

Dezimale

m = - 1.23743 \dots, m = 1.23743 \dots

Schritte zur Lösung

(- 18 m^{2})^{2} - 4 (1 + m^{2}) (81 m^{2} - 49) = 0

Schreibe

(- 18 m^{2})^{2} - 4 (1 + m^{2}) (81 m^{2} - 49)

um:

- 128 m^{2} + 196

- 128 m^{2} + 196 = 0

Löse mit der quadratischen Formel

m_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 128 ) \cdot 196}{2 ( - 128 )}

0^{2} - 4 (- 128) \cdot 196 = 2242

m_{1, 2} = \frac{- 0 \pm 224 2}{2 ( - 128 )}

Trenne die Lösungen

m_{1} = \frac{- 0 + 224 2}{2 ( - 128 )}, m_{2} = \frac{- 0 - 224 2}{2 ( - 128 )}

m = \frac{- 0 + 224 2}{2 ( - 128 )} : - \frac{7}{4 2}

m = \frac{- 0 - 224 2}{2 ( - 128 )} : \frac{7}{4 2}

Die Lösungen für die quadratische Gleichung sind:

m = - \frac{7}{4 2}, m = \frac{7}{4 2}

p^{2} + p - 2 = 0

f a c t or x^{4} - 8 x^{2} + 7

- 14 x + 3 = - 9 x - 12

x^{2} + 7 x + 6 \geq 0

(x - 1) (x + 4) = 36