faktorisieren 6.25m^8-0.49n^6

Lösung

faktorisieren

6.25 m^{8} - 0.49 n^{6}

(2.5 m^{4} + 0.7 n^{3}) (2.5 m^{4} - 0.7 n^{3})

Schritte zur Lösung

6.25 m^{8} - 0.49 n^{6}

Schreibe

6.25 m^{8} - 0.49 n^{6}

um:

(6.25 m^{4})^{2} - (0.49 n^{3})^{2}

= (6.25 m^{4})^{2} - (0.49 n^{3})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(6.25 m^{4})^{2} - (0.49 n^{3})^{2} = (6.25 m^{4} + 0.49 n^{3}) (6.25 m^{4} - 0.49 n^{3})

= (6.25 m^{4} + 0.49 n^{3}) (6.25 m^{4} - 0.49 n^{3})

6.25 = 2.5

= (2.5 m^{4} + 0.49 n^{3}) (6.25 m^{4} - 0.49 n^{3})

0.49 = 0.7

= (2.5 m^{4} + 0.7 n^{3}) (6.25 m^{4} - 0.49 n^{3})

6.25 = 2.5

= (2.5 m^{4} + 0.7 n^{3}) (2.5 m^{4} - 0.49 n^{3})

0.49 = 0.7

= (2.5 m^{4} + 0.7 n^{3}) (2.5 m^{4} - 0.7 n^{3})

f a c t or 2 cos^{2} (x) + 3 cos (x) + 1

f a c t or - (+ 2)

f a c t or w^{3} y^{12} + 1728 x^{6}

f a c t or 2 x + x

f a c t or (x + 1) (x + 2) (x + 3) (x + 4) + 1