faktorisieren 4r^2-pir^2

Lösung

faktorisieren

4 r^{2} - π r^{2}

- (π + 2) (π - 2) r^{2}

Schritte zur Lösung

4 r^{2} - π r^{2}

Schreibe

4 r^{2}

um:

(2 r)^{2}

= (2 r)^{2} - π r^{2}

Schreibe

(2 r)^{2} - π r^{2}

um:

(2 r)^{2} - (π r)^{2}

= (2 r)^{2} - (π r)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(2 r)^{2} - (π r)^{2} = (2 r + π r) (2 r - π r)

= (2 r + π r) (2 r - π r)

Faktorisiere

2 r + π r : r (π + 2)

= (π + 2) r (2 r - π r)

Faktorisiere

2 r - π r : - r (π - 2)

= - r (π + 2) r (π - 2)

Fasse zusammen

= - (π + 2) (π - 2) r^{2}

f a c t or 3 (x + y)^{2} - 4 (x + y) - 4

f a c t or 5 (x + y)^{2} - 17 (x + y) + 6

s im pl i f y \frac{63}{1 + 8 e ^{- 315 (5)}}

\frac{d}{d t} ((x) (t^{2}))

f a c t or - 3 sin (40 t + 50)