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受欢迎的代数 >

10n^2-n-20610=0

解答

10 n^{2} - n - 20610 = 0

解答

n = \frac{1 + 824401}{20}, n = \frac{1 - 824401}{20}

+1

十进制

n = 45.44826 \dots, n = - 45.34826 \dots

求解步骤

10 n^{2} - n - 20610 = 0

使用求根公式求解

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 20610 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 20610) = 824401

n_{1, 2} = \frac{- ( - 1 ) \pm 824401}{2 \cdot 10}

将解分隔开

n_{1} = \frac{- ( - 1 ) + 824401}{2 \cdot 10}, n_{2} = \frac{- ( - 1 ) - 824401}{2 \cdot 10}

n = \frac{- ( - 1 ) + 824401}{2 \cdot 10} : \frac{1 + 824401}{20}

n = \frac{- ( - 1 ) - 824401}{2 \cdot 10} : \frac{1 - 824401}{20}

二次方程组的解是:

n = \frac{1 + 824401}{20}, n = \frac{1 - 824401}{20}

作图

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