faktorisieren 5+(2x+3)2-(3x+2)(x+1)

Lösung

faktorisieren

5 + (2 x + 3) 2 - (3 x + 2) (x + 1)

- 3 (x - \frac{109 - 1}{6}) (x - \frac{- 1 - 109}{6})

Schritte zur Lösung

5 + (2 x + 3) \cdot 2 - (3 x + 2) (x + 1)

Multipliziere aus

5 + (2 x + 3) \cdot 2 - (3 x + 2) (x + 1) : - 3 x^{2} - x + 9

= - 3 x^{2} - x + 9

Faktorisiere

- 3 x^{2} - x + 9 : - 3 (x - \frac{- 1 + 109}{6}) (x - \frac{- 1 - 109}{6})

= - 3 (x - \frac{109 - 1}{6}) (x - \frac{- 1 - 109}{6})

f a c t or (4 x^{2})^{2} - 8 (4 x^{2}) - 105

\frac{d}{d x} ((cos (x + y))^{2})

f a c t or m p + m q - 3 p - 3 q

f a c t or ln (s) in x (sin (x))

f a c t or a e^{4 x} - a e^{- 4 x}