de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

faktorisieren m^3n^6+d^3

Lösung

faktorisieren

m^{3} n^{6} + d^{3}

Lösung

(m n^{2} + d) (m^{2} n^{4} - m n^{2} d + d^{2})

Schritte zur Lösung

m^{3} n^{6} + d^{3}

Schreibe

m^{3} n^{6}

um:

(m n^{2})^{3}

= (m n^{2})^{3} + d^{3}

Wende Formel zur Summe von dritten Potenzen an:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(m n^{2})^{3} + d^{3} = (m n^{2} + d) ((m n^{2})^{2} - d m n^{2} + d^{2})

= (d + m n^{2}) (d^{2} - d m n^{2} + (m n^{2})^{2})

Vereinfache

(m n^{2} + d) ((m n^{2})^{2} - d m n^{2} + d^{2}) : (m n^{2} + d) (m^{2} n^{4} - m n^{2} d + d^{2})

= (m n^{2} + d) (m^{2} n^{4} - m n^{2} d + d^{2})

Beliebte Beispiele

faktorisieren 4y^2+12-7

f a c t or 4 y^{2} + 12 - 7

faktorisieren y^2-14+49

f a c t or y^{2} - 14 + 49

faktorisieren sqrt(x+3)-sqrt(x+3)

f a c t or x + 3 - x + 3

faktorisieren sqrt(9x^2+9)

f a c t or 9 x^{2} + 9

f (x) = 11 x - 18