展开 10(1-e^{-0.5x})

解答

展开

10 (1 - e^{- 0.5 x})

10 - 10 e^{- 0.5 x}

求解步骤

10 (1 - e^{- 0.5 x})

使用分配律:

a (b - c) = ab - a c

a = 10, b = 1, c = e^{- 0.5 x}

= 10 \cdot 1 - 10 e^{- 0.5 x}

数字相乘:

10 \cdot 1 = 10

= 10 - 10 e^{- 0.5 x}

e x p an d \frac{( x - y ) ^{2}}{x + y}

e x p an d π ((2 n + 1) - \frac{π}{2})

e x p an d a (e^{2} p q^{2} b^{2} - c)

e x p an d 2 π (k + \frac{k}{5})

e x p an d (A + B \cdot t) \cdot e^{t}