erweitern ((3x+1)(x+2))/2

Lösung

erweitern

\frac{( 3 x + 1 ) ( x + 2 )}{2}

\frac{3 x ^{2}}{2} + \frac{7 x}{2} + 1

Schritte zur Lösung

\frac{( 3 x + 1 ) ( x + 2 )}{2}

Multipliziere aus

(3 x + 1) (x + 2) : 3 x^{2} + 7 x + 2

= \frac{3 x ^{2} + 7 x + 2}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 7 x + 2}{2} = \frac{3 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

= \frac{3 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

Wende Regel an

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{3 x ^{2}}{2} + \frac{7 x}{2} + 1

e x p an d d (3 x y + e^{y})

e x p an d \frac{2 ^{3}}{2 ^{5}}

e x p an d \frac{32 x}{( x ^{2} + 3 ) ^{2}}

e x p an d \frac{( 3 - 5 ( x + y ) ) ^{4}}{y}

e x p an d \frac{( 3 x + 7 ) ^{3}}{9261}