展开 (((8-b))/3)^2

解答

展开

(\frac{( 8 - b )}{3})^{2}

\frac{64}{9} - \frac{16 b}{9} + \frac{b ^{2}}{9}

求解步骤

(\frac{8 - b}{3})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 8 - b ) ^{2}}{3 ^{2}}

(8 - b)^{2} = 64 - 16 b + b^{2}

= \frac{64 - 16 b + b ^{2}}{3 ^{2}}

3^{2} = 9

= \frac{64 - 16 b + b ^{2}}{9}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 - 16 b + b ^{2}}{9} = \frac{64}{9} - \frac{16 b}{9} + \frac{b ^{2}}{9}

= \frac{64}{9} - \frac{16 b}{9} + \frac{b ^{2}}{9}

e x p an d (\frac{x - y}{2} - 6 + 120 = 0) (2)

e x p an d \frac{b}{( s ^{2} ( s + a ) )}

e x p an d \frac{x ^{4} + 1}{x ^{2} ( x - 1 )}

\frac{d}{d y} ((x) (x + y)^{2})

e x p an d (f \circ g) x (3 x - 4) + 2