展开 F(cos(30)-0.25N=0)

解答

展开

F (cos (3 0^{\circ}) - 0.25 N = 0)

0.86602 \dots F - 0.25 NF = 0

求解步骤

F (cos (3 0^{\circ}) - 0.25 N = 0)

= F (cos (3 0^{\circ}) - 0 \cdot 0.25 = N)

使用分配律:

a (b - c) = ab - a c

a = F, b = cos (3 0^{\circ}), c = 0.25 N = 0

F cos (3 0^{\circ}) - F \cdot 0.25 N = 0

cos (3 0^{\circ}) F - 0.25 NF = 0

乘开

cos (3 0^{\circ}) F - 0.25 NF : 0.86602 \dots F - 0.25 NF

0.86602 \dots F - 0.25 NF = 0

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