展開する h(x)(4x^2+3x+h(x)=0)

解

展開する

h (x) (4 x^{2} + 3 x + h (x) = 0)

4 x^{2} h (x) + 3 x h (x) + h (x)^{2} = 0

解答ステップ

h (x) (4 x^{2} + 3 x + h (x) = 0)

= h (x) (4 x^{2} + 3 x + 0 = h (x))

括弧を分配する

h (x) \cdot 4 x^{2} + h (x) \cdot 3 x + h (x) h (x) = 0

4 x^{2} h (x) + 3 x h (x) + h (x) h (x) = 0

拡張

4 x^{2} h (x) + 3 x h (x) + h (x) h (x) : 4 x^{2} h (x) + 3 x h (x) + h (x)^{2}

4 x^{2} h (x) + 3 x h (x) + h (x)^{2} = 0