erweitern ((x-3)^2)/9

Lösung

erweitern

\frac{( x - 3 ) ^{2}}{9}

\frac{x ^{2}}{9} - \frac{2 x}{3} + 1

Schritte zur Lösung

\frac{( x - 3 ) ^{2}}{9}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{x ^{2} - 6 x + 9}{9}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 9}{9} = \frac{x ^{2}}{9} - \frac{6 x}{9} + \frac{9}{9}

= \frac{x ^{2}}{9} - \frac{6 x}{9} + \frac{9}{9}

Wende Regel an

\frac{a}{a} = 1

\frac{9}{9} = 1

= \frac{x ^{2}}{9} - \frac{6 x}{9} + 1

Streiche

\frac{6 x}{9} : \frac{2 x}{3}

= \frac{x ^{2}}{9} - \frac{2 x}{3} + 1

e x p an d \frac{3}{( 3 u ^{2} + 1 ) ^{2}}

e x p an d 3 ((x + h) - 1)^{2}

e x p an d - sin (π t) (i - j)

e x p an d s (1 + t, - 2 + 5 t, 21 + 2 t)

e x p an d (y + x) d y - (y - x) d x