展开 (2(a-mc+ne)+mr(e-l))r(e-l)

解答

展开

(2 (a - m c + n e) + m r (e - l)) r (e - l)

2 e a r - 2 e m cr + 2 e^{2} n r - 2 a l r + 2 l m cr - 2 e l n r + e^{2} m r^{2} - 2 e l m r^{2} + l^{2} m r^{2}

求解步骤

(2 (a - m c + n e) + m r (e - l)) r (e - l)

= r (2 (a - m c + e n) + m r (e - l)) (e - l)

乘开

(2 (a - m c + n e) + m r (e - l)) (e - l) : 2 e a - 2 e m c + 2 e^{2} n - 2 a l + 2 l m c - 2 e l n + e^{2} m r - 2 e l m r + l^{2} m r

= r (2 e a - 2 e m c + 2 e^{2} n - 2 a l + 2 l m c - 2 e l n + e^{2} m r - 2 e l m r + l^{2} m r)

乘开

r (2 e a - 2 e m c + 2 e^{2} n - 2 a l + 2 l m c - 2 e l n + e^{2} m r - 2 e l m r + l^{2} m r) : 2 e a r - 2 e m cr + 2 e^{2} n r - 2 a l r + 2 l m cr - 2 e l n r + e^{2} m r^{2} - 2 e l m r^{2} + l^{2} m r^{2}

= 2 e a r - 2 e m cr + 2 e^{2} n r - 2 a l r + 2 l m cr - 2 e l n r + e^{2} m r^{2} - 2 e l m r^{2} + l^{2} m r^{2}

e x p an d ln (e - (e + 2) (e - 2))

e x p an d \frac{40}{s ^{2} ( s ^{2} + 16 )}

e x p an d 2 (a - 2 x - 6, - 6 + 2 y) - (4 y + 2, - 5 x - 1)

e x p an d \frac{x + 2}{( x - 2 ) ( 1 - x )}

e x p an d \frac{( c + s ) π - 40 r}{17 r}