簡約 2ln(x^3y 1/2)

解

簡約

2 ln (x^{3} y \frac{1}{2})

6 ln (x) + 2 ln (y) - 2 ln (2)

解答ステップ

2 ln (x^{3} y \frac{1}{2})

対数の規則を適用する:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

2 ln (x^{3} y \frac{1}{2}) = 2 ln (x^{3}) + 2 ln (y) + 2 ln (\frac{1}{2})

= 2 ln (x^{3}) + 2 ln (y) + 2 ln (\frac{1}{2})

対数の規則を適用する:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (x^{3}) = 3 ln (x)

= 2 \cdot 3 ln (x) + 2 ln (y) + 2 ln (\frac{1}{2})

対数の規則を適用する:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{2}) = ln (1) - ln (2)

= 2 \cdot 3 ln (x) + 2 ln (y) + 2 (ln (1) - ln (2))

2 \cdot 3 ln (x) = 6 ln (x)

2 (ln (1) - ln (2)) = - 2 ln (2)

= 6 ln (x) + 2 ln (y) - 2 ln (2)