zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor x,x^2+kx+x=8+k

解答

x, x^{2} + k x + x = 8 + k

解答

x = \frac{- k - 1 + k ^{2} + 6 k + 33}{2}, x = \frac{- k - 1 - k ^{2} + 6 k + 33}{2}

求解步骤

x^{2} + k x + x = 8 + k

将

k

para o lado esquerdo

x^{2} + k x + x - k = 8

将

8

para o lado esquerdo

x^{2} + k x + x - k - 8 = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (k + 1) x - k - 8 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( k + 1 ) \pm ( k + 1 ) ^{2} - 4 \cdot 1 \cdot ( - k - 8 )}{2 \cdot 1}

化简

(k + 1)^{2} - 4 \cdot 1 \cdot (- k - 8) : k^{2} + 6 k + 33

x_{1, 2} = \frac{- ( k + 1 ) \pm k ^{2} + 6 k + 33}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( k + 1 ) + k ^{2} + 6 k + 33}{2 \cdot 1}, x_{2} = \frac{- ( k + 1 ) - k ^{2} + 6 k + 33}{2 \cdot 1}

x = \frac{- ( k + 1 ) + k ^{2} + 6 k + 33}{2 \cdot 1} : \frac{- k - 1 + k ^{2} + 6 k + 33}{2}

x = \frac{- ( k + 1 ) - k ^{2} + 6 k + 33}{2 \cdot 1} : \frac{- k - 1 - k ^{2} + 6 k + 33}{2}

二次方程组的解是:

x = \frac{- k - 1 + k ^{2} + 6 k + 33}{2}, x = \frac{- k - 1 - k ^{2} + 6 k + 33}{2}

作图

流行的例子

(x - 5)^{2} - 3 = 0

x^2-4x+13=0.2+3i

x^{2} - 4 x + 13 = 0.2 + 3 i

-3x^2-298=-60x-1

- 3 x^{2} - 298 = - 60 x - 1

w (2 w - 11) - 8 = 0

5 r^{2} + 15 r + 7 = 0