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受欢迎的代数 >

3q^2-108q+890=0

解答

3 q^{2} - 108 q + 890 = 0

解答

q = \frac{54 + 246}{3}, q = \frac{54 - 246}{3}

+1

十进制

q = 23.22812 \dots, q = 12.77187 \dots

求解步骤

3 q^{2} - 108 q + 890 = 0

使用求根公式求解

q_{1, 2} = \frac{- ( - 108 ) \pm ( - 108 ) ^{2} - 4 \cdot 3 \cdot 890}{2 \cdot 3}

(- 108)^{2} - 4 \cdot 3 \cdot 890 = 2246

q_{1, 2} = \frac{- ( - 108 ) \pm 2 246}{2 \cdot 3}

将解分隔开

q_{1} = \frac{- ( - 108 ) + 2 246}{2 \cdot 3}, q_{2} = \frac{- ( - 108 ) - 2 246}{2 \cdot 3}

q = \frac{- ( - 108 ) + 2 246}{2 \cdot 3} : \frac{54 + 246}{3}

q = \frac{- ( - 108 ) - 2 246}{2 \cdot 3} : \frac{54 - 246}{3}

二次方程组的解是:

q = \frac{54 + 246}{3}, q = \frac{54 - 246}{3}

作图

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